Air Ambulance Helicopter to Winslow, Winslow Road

Friday, 10 July 2026 | 12:54 | From Medbourne

Flight route Air Ambulance Helicopter Medbourne - Winslow, 10 July 2026, 11:54

On Friday, 10 July 2026 at 12:54, a Air Ambulance Helicopter departed from Medbourne to Winslow. It was the Air Ambulance Helicopter with registration number G-TVLY. The flight lasted 9 minutes. During that period, the aircraft travelled 8 miles at an average speed of 50 miles per hour at a maximum altitude of 1325 feet.

Photo of helicopter: G-TVLY
Helicopter: G-TVLY

The helicopter G-TVLY is used as a air ambulance helicopter. The main purpose of this aircraft is to transport a Mobile Medical Team to an incident as quickly as possible, enabling the trauma doctor to provide immediate first aid on site. The aircraft is flying this flight as Air Ambulance Helicopter.

Photo: Tony Melony

Distance travelled
8 miles
1325 feet
dashboard average speed
50 mph
10 minutes
12:54
13:03
Flight tracking overview, altitude and location

Route

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Winslow Road, Buckinghamshire13:03

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Winslow, Buckinghamshire13:02

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Swanbourne, Buckinghamshire13:01

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Mursley, Buckinghamshire13:00

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Little Horwood, Buckinghamshire13:00

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Mursley, Buckinghamshire13:00

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Tattenhoe Park, Milton Keynes12:59

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Westcroft, Milton Keynes12:59

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Vernier Crescent, Milton Keynes12:57

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Medbourne, Milton Keynes12:54

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